# Verify Binary Tree with Same Value

## Question

Verify whether all nodes have the same value in a binary tree.

## Solution

We can traverse the tree with our usual way, like depth-first or breadth-first algorithm. Then pass a value, probably the root value, to compare with the visiting node.

## Example

```
# node structure
class bst_node:
value = None
left = None
right = None
def __init__(self, value, left=None, right=None):
self.value = value
self.left = left
self.right = right
# what to do while visiting the node
def visit(node, value):
return node.value == value # reflect a binary tree
def depth_first_traversal(root):
stack = [root]
value = root.value
result = True
while len(stack) > 0:
node = stack.pop()
result = visit(node, value)
if result == False: break
if node.left: stack.append(node.left)
if node.right: stack.append(node.right)
return result
# a binary tree with all values to be 1
node_05 = bst_node(1)
node_07 = bst_node(1)
node_09 = bst_node(1)
node_11 = bst_node(1)
node_06 = bst_node(1, node_05, node_07)
node_10 = bst_node(1, node_09, node_11)
node_08 = bst_node(1, node_06, node_10)
root = node_08
# main
print depth_first_traversal(root)
```

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